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  • Auras T6C Golden Heatsink Review
  • Auras T6C Golden Heatsink Review

    Author:
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    Benchmarks

    Benchmarks
    The Auras T6C is designed for Pentium 4 up to 3.2Ghz and higher. Here is an overview of the system and testing methodology.

    LanParty Pro875 Rev-A
    Intel Pentium 4 2.4C (SL6EF)
    Auras T6C Golden
    AVC Sunflower II

    I used the included BIOS monitoring software to obtain temperature information from the system. A simple game of Quake 3 provided the 100% processor usage.
    Editors note: Even though the Windows XP task manager reported 100% processor usage we could never attain a 100% of the rated heat output as documented by Intel (see below) when using Quake 3 as a basis for that heat production. Knowing this the game was played until the maximum temperature was attainted and stabilized, or when the round was over.
    Other things to consider when judging software induced heat output.
    a) Clock throttling by the processor at high temperatures.
    b) Normal software isn't designed to produce maximum heat output.
    c) Variances of cooling temperature.
    d) Variances in CPU load.
    e) Inaccuracies in thermal diode readouts.
    Of course the list goes on..

    My testing methodology is aimed to provide a real world look into this heatsink given the test system provided.
    A C/W rating can quickly be calculated using this formula.

    C/W = (CPU temp - Ambient temp)/(Variance(%) * CPU Watts)
    Allowed variance for this test = 75%
    CPU Watts = 66.2W

    0.23 C/W = (36C - 24.5C)/(.75(66.2W))
    For this next test the FSB was cranked up to 220Mhz and the test was re-run. To calculate how the C/W rating has changed we will need to factor in the increased processor wattage. The formula and constants for this is listed below.

    ocC/W = dCPU Watts * (ocMhz / dMhz) * (ocVcore / dVcore)2
    ocMhz = 2640
    dMhz = 2400
    ocVcore = 1.70
    dVcore = 1.525
    The variance still applies for our C/W calcuation
    Allowed variance for this test = 75%
    CPU Watts = 90.3W

    0.22 C/W = (39.5C - 24.5C)/(.75(90.3W))
    Benchmark Conclusion
    Staying true to the nature of a heat pipe the CPU temperature dropped even though the CPU output was increased. This shows that the heatsink was getting more efficient as the temperature difference in the heat pipes increased.

    Keep in mind this calculation is provided for demonstration purposes only and may not reflect the actual lab tested C/W rating, but I think I'm close wink smile